(4-x)^2-(3x+1)(4-x)=0

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Solution for (4-x)^2-(3x+1)(4-x)=0 equation: 



(4-x)^2-(3x+1)(4-x)=0

We add all the numbers together, and all the variables

(-1x+4)^2-(3x+1)(-1x+4)=0

We multiply parentheses ..

-(-3x^2+12x-1x+4)+(-1x+4)^2=0

We get rid of parentheses

3x^2-12x+1x+(-1x+4)^2-4=0

We add all the numbers together, and all the variables

3x^2-11x+(-1x+4)^2-4=0

We move all terms containing x to the left, all other terms to the right

3x^2-11x+(-1x+4)^2=4

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